Embold Pricing 2026
Plans, costs, and free options for Embold
Last updated: February 4, 2026
TL;DR: Embold Pricing
Pricing Model
100% Free
Starting Price
$0
Free Option
Yes ✓
FreeNo credit card required
Pricing Model
Embold is completely free to use. There are no paid tiers, subscription fees, or hidden costs. You get access to all features at no charge.
100% Free - No payment required
Available Plans
Free
Free
- Upto 20k lines of code for your private repositories
Embold vs Competitors: Pricing Comparison
See how Embold pricing compares to similar tools in Code Review
| Tool | Free Tier | Starting Price | Score | |
|---|---|---|---|---|
EmboldCurrentBest Value Prevent technical debt and improve code ... | Yes | Free | —/100 | Details → |
 CodeClimate Automated code review and quality analys... | Yes | $16.67/mo | 80/100 | Pricing → |
SonarQubeTop Rated Code quality and security | Yes | $150/mo | 86/100 | Pricing → |
Trunk Code quality and developer experience to... | Yes | — | 80/100 | Pricing → |
Prices shown are starting prices. Actual pricing may vary based on features and team size.
See all alternatives →Embold Pricing FAQ
How much does Embold cost?
Embold is completely free to use. There are no hidden costs or paid tiers.
Is there a free version of Embold?
Yes, Embold is entirely free to use with all features included.
Does Embold offer a free trial?
Embold is completely free, so no trial is needed.
What are cheaper alternatives to Embold?
Free or freemium alternatives include CodeClimate, SonarQube, Trunk. View our full comparison to find the best value.
How much does Embold cost?
Embold offers a freemium model. It is free for up to 20,000 lines of code for private repositories. For enterprise solutions, a customizable, self-hosted version is available, but specific pricing details for paid tiers are not provided on the available pages.
Is Embold free?
Yes, Embold offers a free tier for up to 20,000 lines of code for private repositories. It also provides free IDE plugins for various development environments.