SVGator Pricing 2026
Plans, costs, and free options for SVGator
Last updated: January 26, 2026
TL;DR: SVGator Pricing
Pricing Model
Freemium
Starting Price
$24/mo
Free Option
Yes ✓
Freemium
Pricing Model
SVGator offers a free tier with basic features, plus paid plans for users who need more advanced functionality.
Free Tier Available
Basic features included at no cost
Paid Upgrades
Premium features with paid plans
Starting at $24/month
Available Plans
Free
Free
- Unlimited exports with watermark
- Basic animation
- Standard quality
Pro
$24/mo
- No watermark
- High-quality exports
- SVG Player API
- Annual billing
Team
$27/mo
- Per user (min 3)
- Collaborative workspaces
- Priority support
- Annual billing
SVGator vs Competitors: Pricing Comparison
See how SVGator pricing compares to similar tools in Design
| Tool | Free Tier | Starting Price | Score | |
|---|---|---|---|---|
SVGatorCurrent SVG animation tool | Yes | $24/mo | —/100 | Details → |
RiveBest Value Interactive animations for apps and game... | Yes | $9/mo | 85/100 | Pricing → |
 Jitter A fast and simple motion design tool on ... | Yes | $12/mo | 71/100 | Pricing → |
 FigmaTop Rated The collaborative design platform | Yes | $15/mo | 95/100 | Pricing → |
Lottie Lightweight animations for web and mobil... | Yes | $15/mo | 88/100 | Pricing → |
After Effects Motion graphics and visual effects | No | $22.99/mo | —/100 | Pricing → |
Prices shown are starting prices. Actual pricing may vary based on features and team size.
See all alternatives →SVGator Pricing FAQ
How much does SVGator cost?
SVGator offers the following plans: Free (Free), Pro ($24/mo), Team ($27/mo). A free tier is available.
Is there a free version of SVGator?
Yes, SVGator offers a free Free plan that includes Unlimited exports with watermark, Basic animation, Standard quality.
Does SVGator offer a free trial?
Check SVGator's official website for current trial offers.
What are cheaper alternatives to SVGator?
Free or freemium alternatives include Rive, Jitter, Figma. View our full comparison to find the best value.